std::bit_width
From cppreference.com
Defined in header <bit>
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template< class T > constexpr T bit_width(T x) noexcept; |
(since C++20) | |
If x
is not zero, calculates the number of bits needed to store the value x
, that is, 1 + floor(log
2(x)). If x
is zero, returns zero.
This overload only participates in overload resolution if T
is an unsigned integer type (that is, unsigned char, unsigned short, unsigned int, unsigned long, unsigned long long, or an extended unsigned integer type).
Return value
Zero if x
is zero; otherwise, one plus the base-2 logarithm of x
, with any fractional part discarded.
Notes
This function is equivalent to return std::numeric_limits<T>::digits - std::countl_zero(x);.
Example
This section is incomplete Reason: no example |
See also
(C++20) |
counts the number of consecutive 0 bits, starting from the most significant bit (function template) |