std::out_ptr
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                    | Defined in header  <memory> | ||
| template< class Pointer = void, class Smart, class... Args > auto out_ptr( Smart& s, Args&&... args ); | (since C++23) | |
Returns an out_ptr_t with deduced template arguments that captures arguments for resetting by reference.
The program is ill-formed if construction of the return value (see below) is ill-formed.
Parameters
| s | - | the object (typically a smart pointer) to adapt | 
| args... | - | the arguments for resetting to capture | 
Return value
std::out_ptr_t<Smart, P, Args&&>(s, std::forward<Args>(args)...), where P is
-  Pointer, ifPointeris not same as void,
- otherwise, Smart::pointer, if it is valid and denotes a type,
- otherwise, Smart::element_type*, if Smart::element_type is valid and denotes a type,
- otherwise, std::pointer_traits<Smart>::element_type*.
Notes
Users may specify the template argument for the template parameter Pointer, in order to interoperate with foreign functions that take a Pointer*.
As all arguments for resetting are captured by reference, the returned out_ptr_t should be a temporary object destroyed at the end of the full-expression containing the call to the foreign function, in order to avoid dangling references.
Example
| This section is incomplete Reason: no example | 
See also
| (C++23) | creates an inout_ptr_twith an associated smart pointer and resetting arguments(function template) | 
| (C++14)(C++20) | creates a unique pointer that manages a new object (function template) | 
| creates a shared pointer that manages a new object (function template) |