std::deque<T,Allocator>::pop_front
From cppreference.com
| void pop_front(); |
||
Removes the first element of the container. If there are no elements in the container, the behavior is undefined.
| Iterators and references to the erased element are invalidated. It is unspecified whether the past-the-end iterator is invalidated if the element is the last element in the container. Other references and iterators are not affected. | (until C++11) |
| Iterators and references to the erased element are invalidated. If the element is the last element in the container, the past-the-end iterator is also invalidated. Other references and iterators are not affected. | (since C++11) |
Parameters
(none)
Return value
(none)
Complexity
Constant.
Exceptions
Does not throw.
Example
Run this code
#include <deque> #include <iostream> auto print = [](const auto& con) { for (auto const& item : con) std::cout << item; std::cout << '\n'; }; int main() { std::deque<char> letters{'A','B','C','D'}; for (char c{letters.back()}; c != 'H' ;) { letters.push_back(++c); print(letters); letters.pop_front(); } }
Output:
ABCDE BCDEF CDEFG DEFGH
See also
| removes the last element (public member function) | |
| inserts an element to the beginning (public member function) |