std::type_identity
From cppreference.com
                    
                                        
                    
                    
                                                            
                    | Defined in header  <type_traits> | ||
| template< class T > struct type_identity; | (since C++20) | |
Provides the member typedef type that names T (i.e., the identity transformation).
The behavior of a program that adds specializations for type_identity is undefined.
Member types
| Name | Definition | 
| type | T | 
Helper types
| template< class T > using type_identity_t = typename type_identity<T>::type; | (since C++20) | |
Possible implementation
| template< class T > struct type_identity { using type = T; }; | 
Notes
type_identity can be used to establish non-deduced contexts in template argument deduction.
Feature testing macro: __cpp_lib_type_identity
Example
Run this code
#include <iostream> #include <type_traits> template <class T> T foo(T a, T b) { return a + b; } template <class T> T bar(T a, std::type_identity_t<T> b) { return a + b; } int main() { // foo(4.2, 1); // error, deduced conflicting types for 'T' std::cout << bar(4.2, 1) << '\n'; // OK, calls bar<double> }
Output:
5.2