std::adjacent_find
Defined in header <algorithm>
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template< class ForwardIt >
ForwardIt adjacent_find( ForwardIt first, ForwardIt last ); |
(1) | |
template< class ForwardIt, BinaryPredicate p >
ForwardIt adjacent_find( ForwardIt first, ForwardIt last, BinaryPredicate p ); |
(2) | |
Searches the range [first, last)
for two consecutive identical elements. The first version uses operator==
to compare the elements, the second version uses the given binary predicate p
.
Contents |
[edit] Parameters
first, last | - | the range of elements to examine | |||||||||
p | - | binary predicate which returns true if the elements should be treated as equal. The signature of the predicate function should be equivalent to the following:
The signature does not need to have const &, but the function must not modify the objects passed to it. |
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Type requirements | |||||||||||
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ForwardIt must meet the requirements of ForwardIterator .
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[edit] Return value
an iterator to the first of the identical elements. If no such elements are found, last
is returned
[edit] Complexity
Exactly the smaller of (result - first) + 1
and (last - first) - 1
applications of the predicate where result
is the return value.
[edit] Possible implementation
First version |
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template<class ForwardIt> ForwardIt adjacent_find(ForwardIt first, ForwardIt last) { if (first == last) { return last; } ForwardIt next = first; ++next; for (next != last; ++next, ++first) { if (*first == *next) { return first; } } return last; } |
Second version |
template<class ForwardIt, BinaryPredicate p> ForwardIt adjacent_find(ForwardIt first, ForwardIt last, BinaryPredicate p) { if (first == last) { return last; } ForwardIt next = first; ++next; for (next != last; ++next, ++first) { if (p(*first, *next)) { return first; } } return last; } |
[edit] Example
The following code finds a pair of equivalent integers in an array of intergers.
#include <algorithm> #include <iostream> int main() { std::vector<int> v1{0, 1, 2, 3, 40, 40, 5}; std::vector<int>::iterator result; result = std::adjacent_find(v1.begin(), v1.end()); if (result == v1.end()) { std::cout << "no matching adjacent elements"; } else { std::cout << "match at: " << std::distance(v1.begin(), result); } }
Output:
match at: 4
[edit] See also
removes consecutive duplicate elements in a range (function template) |