std::compare_strong_order_fallback
| Defined in header <compare>
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| inline namespace /* unspecified */ { inline constexpr /* unspecified */ |
(since C++20) | |
| Call signature |
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| template< class T, class U > requires /* see below */ |
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Performs three-way comparison on t an u and produces a result of type std::strong_ordering, even if the operator <=> is unavailable.
Let t and u be expressions and T and U denote decltype((t)) and decltype((u)) respectively, std::compare_strong_order_fallback(t, u) is expression-equivalent to:
- If std::is_same_v<std::decay_t<T>, std::decay_t<U>> == true:
- the expression is expression-equivalent to std::strong_order(t, u), if it is a well-formed expression;
- Otherwise, if t == u and t < u are both well-formed and convertible to bool, the expression is expression-equivalent to
t == u ? std::strong_ordering::equal : t < u ? std::strong_ordering::less : std::strong_ordering::greater
- except that
tanduare evaluated only once.
- except that
- In all other cases, std::compare_strong_order_fallback(t, u) is ill-formed.
Expression-equivalent
Expression e is expression-equivalent to expression f, if e and f have the same effects, either are both potentially-throwing or are both not potentially-throwing (i.e. noexcept(e) == noexcept(f)), and either are both constant subexpressions or are both not constant subexpressions.
Customization point objects
The name std::compare_strong_order_fallback denotes a customization point object, which is a function object of a literal semiregular class type (denoted, for exposition purposes, as compare_strong_order_fallback_ftor). All instances of compare_strong_order_fallback_ftor are equal. Thus, std::compare_strong_order_fallback can be copied freely and its copies can be used interchangeably.
Given a set of types Args..., if std::declval<Args>()... meet the requirements for arguments to std::compare_strong_order_fallback above, compare_strong_order_fallback_ftor will satisfy std::invocable<const compare_strong_order_fallback_ftor&, Args...>. Otherwise, no function call operator of compare_strong_order_fallback_ftor participates in overload resolution.
Example
| This section is incomplete Reason: no example |
See also
| (C++20) |
performs 3-way comparison and produces a result of type std::strong_ordering (customization point object) |