std::strong_order
| Defined in header <compare>
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| inline namespace /* unspecified */ { inline constexpr /* unspecified */ strong_order = /* unspecified */; |
(since C++20) | |
| Call signature |
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| template< class T, class U > requires /* see below */ |
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Compares two values using 3-way comparison and produces a result of type std::strong_ordering
Let t and u be expressions and T and U denote decltype((t)) and decltype((u)) respectively, std::strong_order(t, u) is expression-equivalent to:
- If std::is_same_v<std::decay_t<T>, std::decay_t<U>> == true:
- std::strong_ordering(strong_order(t, u)), if it is a well-formed expression with overload resolution performed in a context that does not include a declaration of
std::strong_order, - otherwise, if
Tis a floating-point type:- if std::numeric_limits<T>::is_iec559 is true, performs the ISO/IEC/IEEE 60559 totalOrder comparison of floating-point values and returns that result as a value of type std::strong_ordering (note: this comparison can distinguish between the positive and negative zero and between the NaNs with different representations),
- otherwise, yields a value of type std::strong_ordering that is consistent with the ordering observed by
T's comparison operators,
- otherwise, std::strong_ordering(std::compare_three_way()(t, u)) if it is well-formed,
- other the expression is ill-formed, which can result in substitution failure when it appears in the immediate context of a template instantiation.
- std::strong_ordering(strong_order(t, u)), if it is a well-formed expression with overload resolution performed in a context that does not include a declaration of
- Otherwise, std::strong_order(t, u) is ill-formed.
Expression-equivalent
Expression e is expression-equivalent to expression f, if e and f have the same effects, either are both potentially-throwing or are both not potentially-throwing (i.e. noexcept(e) == noexcept(f)), and either are both constant subexpressions or are both not constant subexpressions.
Customization point objects
The name std::strong_order denotes a customization point object, which is a function object of a literal semiregular class type (denoted, for exposition purposes, as strong_order_ftor). All instances of strong_order_ftor are equal. Thus, std::strong_order can be copied freely and its copies can be used interchangeably.
Given a set of types Args..., if std::declval<Args>()... meet the requirements for arguments to std::strong_order above, strong_order_ftor will satisfy std::invocable<const strong_order_ftor&, Args...>. Otherwise, no function call operator of strong_order_ftor participates in overload resolution.
Notes
Strict total order of IEEE floating-point types
Let x and y be values of same IEEE floating-point type, and total_order_less(x, y) be the boolean result indicating if x precedes y in the strict total order defined by totalOrder in ISO/IEC/IEEE 60559.
(total_order_less(x, y) || total_order_less(y, x)) == false if and only if x and y have the same bit pattern.
- if neither
xnoryis NaN:- if
x < y, then total_order_less(x, y) == true; - if
x == y,- if
xis negative zero andyis positive zero, total_order_less(x, y) == true, - if
xis not zero andx's exponent field is less thany's, then total_order_less(x, y) == (x > 0) (only meaningful for decimal floating-point number);
- if
- if
- if either
xoryis NaN:- if
xis negative NaN andyis not negative NaN, then total_order_less(x, y) == true, - if
xis not positive NaN andyis positive NaN, then total_order_less(x, y) == true, - if both
xandyare NaNs with the same sign andx's mantissa field is less thany's, then total_order_less(x, y) == !std::signbit(x).
- if
Example
| This section is incomplete Reason: no example |
See also
| (C++20) |
the result type of 3-way comparison that supports all 6 operators and is substitutable (class) |
| (C++20) |
performs 3-way comparison and produces a result of type std::weak_ordering (customization point object) |
| (C++20) |
performs 3-way comparison and produces a result of type std::partial_ordering (customization point object) |
performs 3-way comparison and produces a result of type std::strong_ordering, even if operator<=> is unavailable (customization point object) |