std::chrono::operator==,<=>(std::chrono::year_month_day)

 

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C-style date and time

 

std::chrono::year_month_day

Member functions

year_month_day::year_month_day

year_month_day::operator+=year_month_day::operator-=

year_month_day::yearyear_month_day::monthyear_month_day::day

year_month_day::operator sys_daysyear_month_day::operator local_days

year_month_day::ok

Nonmember functions

operator==operator<=>

operator+operator-

operator<<

from_stream

Helper classes

formatter<std::chrono::year_month_day>

 

constexpr bool operator==( const std::chrono::year_month_day& x,                            const std::chrono::year_month_day& y ) noexcept;	(1)	(since C++20)
constexpr std::strong_ordering     operator<=>( const std::chrono::year_month_day& x,                  const std::chrono::year_month_day& y ) noexcept;	(2)	(since C++20)

Compares the two year_month_day objects x and y. This is a lexicographical comparison: the year() is compared first, then month(), then day().

Return value

1) x.year() == y.year() && x.month() == y.month() && x.day() == y.day()

2) If x.year() <=> y.year != 0, x.year() <=> y.year; otherwise if x.month() <=> y.month() != 0, x.month() <=> y.month(); otherwise x.day() <=> y.day()

Notes

If both x and y represent valid dates (x.ok() && y.ok() == true), the result of the lexicographical comparison is consistent with the calendar order.