std::chrono::operator==,<=>(std::chrono::year_month_day_last)
From cppreference.com
< cpp | chrono | year month day last
constexpr bool operator==(const std::chrono::year_month_day_last& x, const std::chrono::year_month_day_last& y) noexcept; |
(1) | (since C++20) |
constexpr std::strong_ordering operator<=>( const std::chrono::year_month_day_last& x, |
(2) | (since C++20) |
Compares the two year_month_day_last
objects x
and y
. This is a lexicographical comparison: the year() is compared first, then month().
Return value
1) x.year() == y.year() && x.month() == y.month()
2) x.year() <=> y.year() != 0 ? x.year() <=> y.year() : x.month() <=> y.month()
Notes
If both x
and y
represent valid dates (x.ok() && y.ok() == true), the result of the lexicographical comparison is consistent with the calendar order.